From : Marty Leipzig To : All Subj : Flood Math Ä If, for no other reason to educate som

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From : Marty Leipzig
To   : All
Subj : Flood Math

Ä If, for no other reason to educate some and irritate others,
what follows is a mathematical treatise on the impossibility of a
Biblical Great Flood...

In order to flood the Earth to the Biblical depth of "10
cubits" above the highest mountains of the Earth; you would
need some 4.427 billion cubic kilometers of water. The mass of
this water would be 4.427 x 10^21 kilograms. The current amount
of water in the Earth's hydrosphere is only 1.37 billion cubic
kilometers. So, where did the other 2 hydrospheres full of
water come from? It could not come from water vapor (or clouds)
because the atmospheric pressure would be 842 times greater
than it is now. Further, the latent heat relaeased when the
vapor condenses into liquid would be enough to raise the
temperature of the Earth's atmosphere to 3,570 C (6,458 F).

Someone once suggested that a "Vapor Canopy" covered the Earth,
and this is where all that water came from. Not so at all. What
would keep that water in orbit above the Earth? This niggling
little property called gravity would cause it to fall. Why
should that take 40 days and 40 nights?  Further, this mass of
water (some 4.427 X 10^21 Kg) stores a tremendous amount of
potential energy which would be converted to kinetic energy
when the water falls and would be converted to heat when it
strikes the Earth. This potential energy (Ep=M*g*H; where
M=mass of water, g=gravitational constant and H=height of water
above the Earth's surface) could be calculated. If 4.427 x 10^21
is divided by 40 days, it yields 1.107 x 10^20 Kg/day. If H=16,000m
(approximately 10 miles), the released energy, per day, would
equal 1.735 x 10^25 joules. The amount of energy the Earth
would have to radiate per m^2/s is energy divided by surface
area of the Earth times the number of seconds in one day; thus:
Ep=1.735 x 10^25/(4*3.14159*((6386)^2)*86,400) =
391,935.096 j/m^2/s.

The Earth currently radiates 215 j/m^2/s at an average
temperature of 280 K. Using the Stephan-Boltzmann fourth power
law to calculate temperature increase:

E(increase)/E(normal)=T^4(increase)/T^4(normal); so

E(normal) = 215
E(increase) = 391,935.096
T(normal) = 280  (turn the crank, and...)
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T(increase) = 1,800 K.

The temperature of the Earth would have to rise 1,800 degrees.
Further, the water level would rise an average of 14 cm.
per minute for 40 days. In 13 minutes, the water level would be
over 2 m. in depth. Further, water under standard pressure
would not exist as a liquid at 1,800 K.

So much for that flood...

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E-Mail Fredric L. Rice / The Skeptic Tank