From : Marty Leipzig To : All Subj : Flood Math If, for no other reason to educate som

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From : Marty Leipzig To : All Subj : Flood Math If, for no other reason to educate some and irritate others, what follows is a mathematical treatise on the impossibility of a Biblical Great Flood... In order to flood the Earth to the Biblical depth of "10 cubits" above the highest mountains of the Earth; you would need some 4.427 billion cubic kilometers of water. The mass of this water would be 4.427 x 10^21 kilograms. The current amount of water in the Earth's hydrosphere is only 1.37 billion cubic kilometers. So, where did the other 2 hydrospheres full of water come from? It could not come from water vapor (or clouds) because the atmospheric pressure would be 842 times greater than it is now. Further, the latent heat relaeased when the vapor condenses into liquid would be enough to raise the temperature of the Earth's atmosphere to 3,570 C (6,458 F). Someone once suggested that a "Vapor Canopy" covered the Earth, and this is where all that water came from. Not so at all. What would keep that water in orbit above the Earth? This niggling little property called gravity would cause it to fall. Why should that take 40 days and 40 nights? Further, this mass of water (some 4.427 X 10^21 Kg) stores a tremendous amount of potential energy which would be converted to kinetic energy when the water falls and would be converted to heat when it strikes the Earth. This potential energy (Ep=M*g*H; where M=mass of water, g=gravitational constant and H=height of water above the Earth's surface) could be calculated. If 4.427 x 10^21 is divided by 40 days, it yields 1.107 x 10^20 Kg/day. If H=16,000m (approximately 10 miles), the released energy, per day, would equal 1.735 x 10^25 joules. The amount of energy the Earth would have to radiate per m^2/s is energy divided by surface area of the Earth times the number of seconds in one day; thus: Ep=1.735 x 10^25/(4*3.14159*((6386)^2)*86,400) = 391,935.096 j/m^2/s. The Earth currently radiates 215 j/m^2/s at an average temperature of 280 K. Using the Stephan-Boltzmann fourth power law to calculate temperature increase: E(increase)/E(normal)=T^4(increase)/T^4(normal); so E(normal) = 215 E(increase) = 391,935.096 T(normal) = 280 (turn the crank, and...) ---------------------- T(increase) = 1,800 K. The temperature of the Earth would have to rise 1,800 degrees. Further, the water level would rise an average of 14 cm. per minute for 40 days. In 13 minutes, the water level would be over 2 m. in depth. Further, water under standard pressure would not exist as a liquid at 1,800 K. So much for that flood...


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